If \(\displaystyle\int_0^1 \dfrac{e^t}{1+t}dt=a\), then \(\displaystyle\int_0^1 \dfrac{e^t}{(1+t)^2}dt=\)

If \(\displaystyle\int_0^1 \dfrac{e^t}{1+t}dt=a\), then \(\displayst

1.	If \(\displaystyle\int_0^1 \dfrac{e^t}{1+t}dt=a\), then \(\displaystyle\int_0^1 \dfrac{e^t}{(1+t)^2}dt=\)
A.	\(a-1+\dfrac{e}{2}\)
B.	\(a+1+\dfrac{e}{2}\)
C.	\(a-1-\dfrac{e}{2}\)
D.	\(a+1-\dfrac{e}{2}\)
Answer» E.

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If \(\displaystyle\int_0^1 \dfrac{e^t}{1+t}dt=a\), then \(\displaystyle\int_0^1 \dfrac{e^t}{(1+t)^2}dt=\)

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