If \(cosx\frac{{dy}}{{dx}} - ysinx = 6x,\left( {0 < x < \frac{\pi }{2}} \right)\;{\rm{and}}\;y\left( {\frac{\pi }{3}} \right) = 0,\;{\rm{then}}\;y\left( {\frac{\pi }{6}} \right)\) is equal to:

\(- \frac{{{\pi ^2}}}{{4\sqrt 3 }}\)

\(\frac{{{\pi ^2}}}{{2\sqrt 3 }}\)

\(- \frac{{{\pi ^2}}}{{2\sqrt 3 }}\)

If \(cosx\frac{{dy}}{{dx}} - ysinx = 6x,\left( {0 < x < \frac{\pi }{2}

1.	If \(cosx\frac{{dy}}{{dx}} - ysinx = 6x,\left( {0 < x < \frac{\pi }{2}} \right)\;{\rm{and}}\;y\left( {\frac{\pi }{3}} \right) = 0,\;{\rm{then}}\;y\left( {\frac{\pi }{6}} \right)\) is equal to:
A.	\(\frac{{{\pi ^2}}}{{2\sqrt 3 }}\)
B.	\(- \frac{{{\pi ^2}}}{2}\)
C.	\(- \frac{{{\pi ^2}}}{{2\sqrt 3 }}\)
D.	\(- \frac{{{\pi ^2}}}{{4\sqrt 3 }}\)
Answer» D. \(- \frac{{{\pi ^2}}}{{4\sqrt 3 }}\)

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If \(cosx\frac{{dy}}{{dx}} - ysinx = 6x,\left( {0 < x < \frac{\pi }{2}} \right)\;{\rm{and}}\;y\left( {\frac{\pi }{3}} \right) = 0,\;{\rm{then}}\;y\left( {\frac{\pi }{6}} \right)\) is equal to:

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