MCQOPTIONS
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| 1. |
If cosec θ = b/a, then \(\frac{\sqrt{3} cot \theta + 1}{tan \theta + \sqrt{3}}\) is equal to: |
| A. | \(\frac{\sqrt{b^2 - a^2}}{a}\) |
| B. | \(\frac{\sqrt{b^2 + b^2}}{b}\) |
| C. | \(\frac{\sqrt{a^2 + b^2}}{b}\) |
| D. | \(\frac{\sqrt{b^2 - a^2}}{b}\) |
| Answer» B. \(\frac{\sqrt{b^2 + b^2}}{b}\) | |