If cos (A + B) = \(\frac{3}{5}\) and sin (A - B) = \(\frac{5}{13}\), where 0 ≤ A, \(B \le \frac{\pi}{4}\), then tan 2B is equal to

• A. \(\frac{11}{34}\)
• B. \(\frac{21}{56}\)
• C. \(\frac{33}{56}\)
• D. 1