MCQOPTIONS
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| 1. |
If cos 27° = x, then the value of tan 63° is: |
| A. | \(\frac{\sqrt{1+x^2}}{x}\) |
| B. | \(\frac{x}{\sqrt{1+x^2}}\) |
| C. | \(\frac{\sqrt{1-x^2}}{x}\) |
| D. | \(\frac{x}{\sqrt{1-x^2}}\) |
| Answer» E. | |