MCQOPTIONS
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| 1. |
If any leap year is selected at random, then the probability of containing 53 Fridays in that year will be |
| A. | \(\frac{1}{7}\) |
| B. | \(\frac{2}{7}\) |
| C. | \(\frac{53}{366}\) |
| D. | \(\frac{7}{53}\) |
| Answer» C. \(\frac{53}{366}\) | |