MCQOPTIONS
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| 1. |
If a2sec2x - b2tan2x = c2 then the value of sec2x + tan2x is equal to (assume b2 ≠ a2) |
| A. | \(\frac{{{b^2} - {a^2} + 2{c^2}}}{{{b^2} + {a^2}}}\) |
| B. | \(\frac{{{b^2} + {a^2} - 2{c^2}}}{{{b^2} - {a^2}}}\) |
| C. | \(\frac{{{b^2} - {a^2} - 2{c^2}}}{{{b^2} + {a^2}}}\) |
| D. | \(\frac{{{b^2} - {a^2}}}{{{b^2} + {a^2} + 2{c^2}}}\) |
| Answer» C. \(\frac{{{b^2} - {a^2} - 2{c^2}}}{{{b^2} + {a^2}}}\) | |