1.

If a2sec2x - b2tan2x = c2 then the value of sec2x + tan2x is equal to (assume b2 ≠ a2)

A. \(\frac{{{b^2} - {a^2} + 2{c^2}}}{{{b^2} + {a^2}}}\)
B. \(\frac{{{b^2} + {a^2} - 2{c^2}}}{{{b^2} - {a^2}}}\)
C. \(\frac{{{b^2} - {a^2} - 2{c^2}}}{{{b^2} + {a^2}}}\)
D. \(\frac{{{b^2} - {a^2}}}{{{b^2} + {a^2} + 2{c^2}}}\)
Answer» C. \(\frac{{{b^2} - {a^2} - 2{c^2}}}{{{b^2} + {a^2}}}\)


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