MCQOPTIONS
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| 1. |
If \(A = \frac{(0.1)^3 + (0.2)^3+(0.3)^3+3(0.005+0.016+0.027)+0.036}{(0.1)^2+(0.2)^2+(0.3)^2+0.04+0.06+0.12}\), then the value of 60A is: |
| A. | 36 |
| B. | 30 |
| C. | 20 |
| D. | 60 |
| Answer» B. 30 | |