1.

If a=3–√−2–√3–√+2–√a=3−23+2 and b=3–√+2–√3–√−2–√,b=3+23−2, then the value of a2ba2b + b2ab2a = ?

A. 1030
B. 970
C. 1025
D. 930
Answer» B. 970


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