1.

If \(a^2 \sec^2 x - b^2 \tan^2 x = c^2\) then the value of \(\sec^2 x + \tan^2 x\) is equal to (assume b2 ≠ a2)

A. \(\dfrac{b^2- a^2 + 2c^2}{b^2 + a^2}\)
B. \(\dfrac{b^2+ a^2 - 2c^2}{b^2 - a^2}\)
C. \(\dfrac{b^2 - a^2 - 2c^2}{b^2 + a^2}\)
D. \(\dfrac{b^2 - a^2}{b^2 + a^2 + 2c^2}\)
Answer» C. \(\dfrac{b^2 - a^2 - 2c^2}{b^2 + a^2}\)


Discussion

No Comment Found