MCQOPTIONS
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| 1. |
If \(a^2 \sec^2 x - b^2 \tan^2 x = c^2\) then the value of \(\sec^2 x + \tan^2 x\) is equal to (assume b2 ≠ a2) |
| A. | \(\dfrac{b^2- a^2 + 2c^2}{b^2 + a^2}\) |
| B. | \(\dfrac{b^2+ a^2 - 2c^2}{b^2 - a^2}\) |
| C. | \(\dfrac{b^2 - a^2 - 2c^2}{b^2 + a^2}\) |
| D. | \(\dfrac{b^2 - a^2}{b^2 + a^2 + 2c^2}\) |
| Answer» C. \(\dfrac{b^2 - a^2 - 2c^2}{b^2 + a^2}\) | |