1.

If 6 tanθ - 5√3sec θ + 12 cot θ = 0, 0° < θ < 90°, then of (cosec θ + secθ) is:

A. \(\frac{{2 + \sqrt 3 }}{2}\)
B. \(\frac{{2\left( {3 + 2\sqrt 3 } \right)}}{3}\)
C. \(\frac{{3 + 2\sqrt 3 }}{2}\)
D. \(\frac{2}{3}\left( {3 + \sqrt 3 } \right)\)
Answer» E.


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