1.

If 4 – 2sin2 θ – 5cos θ = 0, 0°

A. \(\dfrac{1-2\sqrt{3}}{2}\)
B. \(\dfrac{2-\sqrt{3}}{2}\)
C. \(\dfrac{1+2\sqrt{3}}{2}\)
D. \(\dfrac{2+\sqrt{3}}{2}\)
Answer» D. \(\dfrac{2+\sqrt{3}}{2}\)


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