If √3cosθ = sinθ, then the value of \(\frac{4sin^2 \theta - 5 co – McqOptions

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1.	If √3cosθ = sinθ, then the value of \(\frac{4sin^2 \theta - 5 cos \theta}{3 cos \theta + 1}\) is
A.	1/4
B.	1/5
C.	5
D.	2/5
Answer» C. 5

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