If \[2{{x}^{3}}+4{{x}^{2}}+2ax+b\] is exactly divisible by \[{{x}^{2}}-1\],then the value of a and b respectively will be

If \[2{{x}^{3}}+4{{x}^{2}}+2ax+b\] is exactly divisible by \[{{x}^{2}}

1.	If \[2{{x}^{3}}+4{{x}^{2}}+2ax+b\] is exactly divisible by \[{{x}^{2}}-1\],then the value of a and b respectively will be
A.	1, 2
B.	- 1, 4
C.	1, - 2
D.	-1, - 4
Answer» E.

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If \[2{{x}^{3}}+4{{x}^{2}}+2ax+b\] is exactly divisible by \[{{x}^{2}}-1\],then the value of a and b respectively will be

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