If \[{{2}^{2x-y}}=32\]and \[{{2}^{x+y}}=16\] then \[{{a}^{3}}+{{b}^{3}}+{{c}^{3}}-3abc=(a+b+c)({{a}^{2}}+{{b}^{2}}+{{c}^{2}}-ab-bc-ca)\]is equal to

• A. 9
• B. 10
• C. 11         
• D. 13