Given \(\frac{{b + c}}{{11}} = \frac{{c + a}}{{12}} = \frac{{a + b}}{{13}}\) for a ΔABC with usual notion. If \(\frac{{b + c}}{{11}} = \frac{{c + a}}{{12}} = \frac{{a + b}}{{13}}\) then the ordered triad (α, β, γ) has a value:

• A. (7, 19, 25)
• B. (3, 4, 5)
• C. (5, 12, 13)
• D. (19, 7, 25)