Given 2^2+4^2+6^2+....+40^2=11480, then the value of 1^2+2^2+3^2+ .... – McqOptions

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1.	Given 2^2+4^2+6^2+....+40^2=11480, then the value of 1^2+2^2+3^2+ .....+ 20^2 is
A.	2869
B.	2867
C.	2868
D.	2870
Answer» E.

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