\(\frac{{sin\theta [\left( {1 - tan\theta } \right)tan\theta + {{\sec }^2}\theta ]}}{{\left( {1 - \sin \theta } \right)\tan \theta \left( {1 + tan\theta } \right)\left( {sec\theta + tan\theta } \right)}}\) is equal to:

• A. sinθ cosθ
• B. - 1
• C. cosecθ secθ
• D. 1