\[\frac{\mathbf{1}}{\mathbf{1+}{{\mathbf{2}}^{\mathbf{x-y}}}}\mathbf{+}\frac{\mathbf{1}}{\mathbf{1+}{{\mathbf{2}}^{\mathbf{y-x}}}}\mathbf{=?}\]

\[\frac{\mathbf{1}}{\mathbf{1+}{{\mathbf{2}}^{\mathbf{x-y}}}}\mathbf{+

1.	\[\frac{\mathbf{1}}{\mathbf{1+}{{\mathbf{2}}^{\mathbf{x-y}}}}\mathbf{+}\frac{\mathbf{1}}{\mathbf{1+}{{\mathbf{2}}^{\mathbf{y-x}}}}\mathbf{=?}\]
A.	\[x\]
B.	\[x-y\]
C.	1
D.	0
Answer» D. 0

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\[\frac{\mathbf{1}}{\mathbf{1+}{{\mathbf{2}}^{\mathbf{x-y}}}}\mathbf{+}\frac{\mathbf{1}}{\mathbf{1+}{{\mathbf{2}}^{\mathbf{y-x}}}}\mathbf{=?}\]

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