\(\frac{4}{3}{\tan ^2}60^\circ + 3{\cos ^2}30^\circ - 2{\sec ^2}30^\ci – McqOptions

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1.	\(\frac{4}{3}{\tan ^2}60^\circ + 3{\cos ^2}30^\circ - 2{\sec ^2}30^\circ - \frac{3}{4}{\cot ^2}60^\circ \) is equal to∶
A.	\(\frac{8}{3}\)
B.	\(\frac{5}{4}\)
C.	\(\frac{{10}}{3}\)
D.	\(\frac{7}{3}\)
Answer» D. \(\frac{7}{3}\)

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