For the expression cos ( t + 0) the correct Pascal equivalent is – McqOptions

MCQOPTIONS

1.	For the expression cos ( t + 0) the correct Pascal equivalent is
A.	<code>BETA * JCOS (OMEGA * <i>T </i> + THETA) / SQRT (SQR (BETA) + SQR (OMEGA))</code>
B.	<code>BETA COS (OMEGA * <i>T</i> + THETA) / SQRT [SQR (BETA) + SQR (OMEGA)]</code>
C.	<code>BETA COS (OMEGA T + THETA) / SQRT [SQR (BETA) + SQR (OMEGA)]</code>
D.	None of the above
Answer» B. <code>BETA COS (OMEGA * <i>T</i> + THETA) / SQRT [SQR (BETA) + SQR (OMEGA)]</code>

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