1.

For any \({\rm{\theta }} \in \left( {\frac{{\rm{\pi }}}{4},{\rm{\;}}\frac{{\rm{\pi }}}{2}} \right),\) the expression 3(sin θ – cos θ)4 + 6(sin θ + cos θ)2 + 4sin6 θ equals

A. 13 – 4 cos2 θ + 6 sin2 θ cos2 θ
B. 13 – 4 cos6 θ
C. 13 – 4 cos2 θ + 6 cos4 θ
D. 13 – 4 cos4 θ + 2 sin2 θ cos2 θ
Answer» C. 13 – 4 cos2 θ + 6 cos4 θ


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