For 0° < θ < 90°, if\(\frac{{sec\theta \left( {1 - sin\theta } \right)\left( {sec\theta \; + \;tan\theta } \right)}}{{{{\left( {sec\theta - tan\theta } \right)}^2}}} = \frac{{1\; + \;k}}{{1 - k}}\;\)then k is equal to:

• A. sin θ
• B. sec θ
• C. cos θ
• D. cosec θ