1.

For 0° < θ < 90°, if 2 cos2θ = 3 sin θ, then the value of (cosec2θ – cot2θ + cos2θ) is equal to:

A. \(1\frac{1}{2}\)
B. \(2\frac{3}{4}\)
C. \(1\frac{3}{4}\)
D. \(2\frac{1}{4}\)
Answer» D. \(2\frac{1}{4}\)


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