Fine the solution of \(\frac{{{d^2}y}}{{d{x^2}}} = y\) which passes through the origin and the point \(\left( {\ln2,\frac{3}{4}} \right)\)

\(y = \frac{1}{2}{e^x} + {e^{ - x}}\)

\(y = \frac{1}{2}{e^x} - {e^x}\)

\(y = \frac{1}{2}\left( {{e^x} + {e^{ - x}}} \right)\)

\(y = \frac{1}{2}\left( {{e^x} - {e^{ - x}}} \right)\)

Fine the solution of \(\frac{{{d^2}y}}{{d{x^2}}} = y\) which passes t

1.	Fine the solution of \(\frac{{{d^2}y}}{{d{x^2}}} = y\) which passes through the origin and the point \(\left( {\ln2,\frac{3}{4}} \right)\)
A.	\(y = \frac{1}{2}{e^x} - {e^x}\)
B.	\(y = \frac{1}{2}\left( {{e^x} + {e^{ - x}}} \right)\)
C.	\(y = \frac{1}{2}\left( {{e^x} - {e^{ - x}}} \right)\)
D.	\(y = \frac{1}{2}{e^x} + {e^{ - x}}\)
Answer» D. \(y = \frac{1}{2}{e^x} + {e^{ - x}}\)

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