Find the value \[x\]in the expression \[\sqrt{{{\left( \frac{3}{5} \right)}^{1-2x}}}=4\frac{17}{27}.\]

• A.  \[\frac{3}{2}\]                  
• B.         \[\frac{5}{2}\]                  
• C.  \[\frac{7}{2}\]                  
• D.         \[\frac{9}{2}\]