Find the value of x such that \[{{\left( \frac{64}{125} \right)}^{2}}{{\left( \frac{4}{5} \right)}^{4}}{{\left( \frac{16}{25} \right)}^{2x+1}}={{\left( \frac{256}{625} \right)}^{3x}}\]

• A.  \[\frac{3}{2}\]    
• B.  \[\frac{2}{3}\]            
• C.  \[\frac{1}{3}\]                                     
• D.  \[\frac{1}{2}\]