Find the smallest angular frequency for which discrete-time sinusoidal signal with the following fundamental period N = 5 would be periodic.

Question

TuteeHUB · Accepted Answer

${\rm{\Omega }} = \frac{\pi }{5}rad/cycle$

TuteeHUB · Answer

${\rm{\Omega }} = \frac{\pi }{{10}}rad/cycle$

TuteeHUB · Answer

${\rm{\Omega }} = \frac{{2\pi }}{5}rad/cycle$

TuteeHUB · Answer

${\rm{\Omega }} = \frac{{2\pi }}{{15}}rad/cycle$

1.	Find the smallest angular frequency for which discrete-time sinusoidal signal with the following fundamental period N = 5 would be periodic.
A.	\({\rm{\Omega }} = \frac{\pi }{{10}}rad/cycle\)
B.	\({\rm{\Omega }} = \frac{{2\pi }}{5}rad/cycle\)
C.	\({\rm{\Omega }} = \frac{\pi }{5}rad/cycle\)
D.	\({\rm{\Omega }} = \frac{{2\pi }}{{15}}rad/cycle\)
Answer» C. \({\rm{\Omega }} = \frac{\pi }{5}rad/cycle\)

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