Fill in the blanks. (i) $$\frac{{{a}^{2}}-{{b}^{2}}}{a(a-b)}-\frac{a{{b}^{2}}+{{a}^{2}}b}{a{{b}^{2}}}$$ is equal to P . (ii) $$\frac{64{{y}^{4}}+8{{y}^{3}}}{4{{y}^{3}}}$$ is equal to Q . (iii) When we divide $$(38{{a}^{3}}{{b}^{3}}{{c}^{2}}-19{{a}^{4}}{{b}^{2}}c)$$ by $$19{{a}^{2}}bc$$, the result is $$ka{{b}^{2}}c-{{a}^{2}}b$$. Then $$k=\underline{\,\,\,R\,\,\,}$$.

Question

Fill in the blanks. (i) $$\frac{{{a}^{2}}-{{b}^{2}}}{a(a-b)}-\frac{a{{b}^{2}}+{{a}^{2}}b}{a{{b}^{2}}}$$ is equal to    P   . (ii) $$\frac{64{{y}^{4}}+8{{y}^{3}}}{4{{y}^{3}}}$$ is equal to     Q    . (iii) When we divide $$(38{{a}^{3}}{{b}^{3}}{{c}^{2}}-19{{a}^{4}}{{b}^{2}}c)$$ by $$19{{a}^{2}}bc$$, the result is $$ka{{b}^{2}}c-{{a}^{2}}b$$. Then $$k=\underline{\,\,\,R\,\,\,}$$.

TuteeHUB · Accepted Answer

NA

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P Q R $$\frac{(a+b)(b-a)}{ab}$$ $$3(8y+1)$$ 1

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P Q R $$\frac{(a+b\,)(b-a)}{ab}$$ $$3(8y+1)$$ 1

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P Q R $$\frac{(a+b)(a-b)}{ab}$$ $$2(8y+1)$$ 1

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P Q R $$\frac{(a+b)(b-a)}{ab}$$ $$2(8y+1)$$ 2

1.	Fill in the blanks. (i) \[\frac{{{a}^{2}}-{{b}^{2}}}{a(a-b)}-\frac{a{{b}^{2}}+{{a}^{2}}b}{a{{b}^{2}}}\] is equal to P . (ii) \[\frac{64{{y}^{4}}+8{{y}^{3}}}{4{{y}^{3}}}\] is equal to Q . (iii) When we divide \[(38{{a}^{3}}{{b}^{3}}{{c}^{2}}-19{{a}^{4}}{{b}^{2}}c)\] by \[19{{a}^{2}}bc\], the result is \[ka{{b}^{2}}c-{{a}^{2}}b\]. Then \[k=\underline{\,\,\,R\,\,\,}\].
A.	P Q R \[\frac{(a+b)(b-a)}{ab}\] \[3(8y+1)\] 1
B.	P Q R \[\frac{(a+b\,)(b-a)}{ab}\] \[3(8y+1)\] 1
C.	P Q R \[\frac{(a+b)(a-b)}{ab}\] \[2(8y+1)\] 1
D.	P Q R \[\frac{(a+b)(b-a)}{ab}\] \[2(8y+1)\] 2
Answer» E.

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