Equivalent conductance at infinite dilution, \[{{\lambda }^{{}^\circ }}\] of \[N{{H}_{4}}Cl,\,NaOH\] and \[NaCl\] are 128.0,217.8 and \[109.3\text{ }oh{{m}^{-1}}c{{m}^{2}}\text{ }e{{q}^{-1}}\] respectively. The equivalent conductance of \[0.01\text{ }N\text{ }N{{H}_{2}}OH\] is \[9.30\text{ }oh{{m}^{-1}}\,c{{m}^{2}}\text{ }e{{q}^{-1}}\] then the degree of ionization of \[N{{H}_{4}}OH\] at this temperature would be

• A. 0.04                 
• B. 0.1    
• C. 0.39                 
• D. 0.62