Directions: Two signs in each equation have been interchanged. Find them out to get the right result: \[\left( \text{3}\times \text{7} \right)+\left( \text{6}+\text{4} \right)-\left( \text{12}\div \text{4} \right)=\text{14}\]

Directions: Two signs in each equation have been interchanged. Find th

1.	Directions: Two signs in each equation have been interchanged. Find them out to get the right result: \[\left( \text{3}\times \text{7} \right)+\left( \text{6}+\text{4} \right)-\left( \text{12}\div \text{4} \right)=\text{14}\]
A.	\[\times ;+\]
B.	\[-;+\]
C.	\[\times ;\div \]
D.	\[\div ;+\]
Answer» C. \[\times ;\div \]

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Directions: Two signs in each equation have been interchanged. Find them out to get the right result: \[\left( \text{3}\times \text{7} \right)+\left( \text{6}+\text{4} \right)-\left( \text{12}\div \text{4} \right)=\text{14}\]

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