DeMorgan‚Äö√Ñ√∂‚àö√ë‚àö¬•s theorem states that$

Question

TuteeHUB · Accepted Answer

(A + B)‚Äö√Ñ√∂‚àö√ë‚àö¬• = A‚Äö√Ñ√∂‚àö√ë‚àö¬• * B

TuteeHUB · Answer

(AB)‚Äö√Ñ√∂‚àö√ë‚àö¬• = A‚Äö√Ñ√∂‚àö√ë‚àö¬• + B‚Äö√Ñ√∂‚àö√ë‚àö¬•

TuteeHUB · Answer

A‚Äö√Ñ√∂‚àö√ë‚àö¬• + B‚Äö√Ñ√∂‚àö√ë‚àö¬• = A‚Äö√Ñ√∂‚àö√ë‚àö¬•B‚Äö√Ñ√∂‚àö√ë‚àö¬•

TuteeHUB · Answer

None of the Mentioned

1.	DeMorgan‚Äö√Ñ√∂‚àö√ë‚àö¬•s theorem states that$
A.	(AB)‚Äö√Ñ√∂‚àö√ë‚àö¬• = A‚Äö√Ñ√∂‚àö√ë‚àö¬• + B‚Äö√Ñ√∂‚àö√ë‚àö¬•
B.	(A + B)‚Äö√Ñ√∂‚àö√ë‚àö¬• = A‚Äö√Ñ√∂‚àö√ë‚àö¬• * B
C.	A‚Äö√Ñ√∂‚àö√ë‚àö¬• + B‚Äö√Ñ√∂‚àö√ë‚àö¬• = A‚Äö√Ñ√∂‚àö√ë‚àö¬•B‚Äö√Ñ√∂‚àö√ë‚àö¬•
D.	None of the Mentioned
Answer» B. (A + B)‚Äö√Ñ√∂‚àö√ë‚àö¬• = A‚Äö√Ñ√∂‚àö√ë‚àö¬• * B

Discussion