ΔABC ∼ ΔQPR and AB = 8 cm, BC = 12 cm and AC = 6 cm. If ar(ΔABC) ∶ ar(ΔPQR) = 16 ∶ 25, then RQ is equal to

ΔABC ∼ ΔQPR and AB = 8 cm, BC = 12 cm and AC = 6 cm. If ar(ΔABC)

1.	ΔABC ∼ ΔQPR and AB = 8 cm, BC = 12 cm and AC = 6 cm. If ar(ΔABC) ∶ ar(ΔPQR) = 16 ∶ 25, then RQ is equal to
A.	15 cm
B.	12.5 cm
C.	10 cm
D.	7.5 cm
Answer» E.

Discussion

No Comment Found

Related MCQs

PQ and RS are common tangents to two circles intersecting at A and B. AB, when produced both sides, meet the tangents PQ and RS at X and Y, respectively. If AB = 3 cm, XY = 5 cm, then PQ (in cm) will be
If the sum of all interior angles of a regular polygon is twice the sum of all its exterior angles then the polygon is
In an isosceles right-angled triangle, the perimeter is 30 m. Find its area (Approximate)
In ΔPQR, S and T are mid-points of PQ and PR, respectively. If ∠QPR = 75° and ∠PRQ = 40°, then ∠TSQ is:
In the circle below, chord AB is extended to meet the tangent DC at D. If AB = 12 cm and DC = 8 cm, find the length of BD.
If the base and height of a triangle is doubled and tripled respectively. Find the difference between the final and initial area of the triangle.
In a circle with centre O, AC and BD are two chords. AC and BD meet at E when produced. If AB is the diameter and ∠AEB = 68°, then the measure of ∠DOC is:
In the following figure (not to scale), AB = CD and \(\rm\overline{AB}\) and \(\rm\overline{CD}\) are produced to meet at point P. If ∠BAD = 70°, then find ∠P
Consider the following statements:1. The diagonals of a trapezium divide each other proportionally.2. Any line drawn parallel to the parallel sides of a trapezium divides the non-parallel sides proportionally.Which of the above statements is / are correct?
DEF is an isosceles triangle with such that DE = DF = 60 cm and EF = 96 cm. DG is a median to base EF. What is the length (in cm) of DG?

ΔABC ∼ ΔQPR and AB = 8 cm, BC = 12 cm and AC = 6 cm. If ar(ΔABC) ∶ ar(ΔPQR) = 16 ∶ 25, then RQ is equal to

Discussion

No Comment Found

Related MCQs

Reply to Comment