MCQOPTIONS
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| 1. |
Consider the differential equation, \({{\rm{y}}^2}{\rm{dx}} + \left( {{\rm{x}} - \frac{1}{{\rm{y}}}} \right){\rm{dy}} = 0\). If value of y is 1 when x = 1, then the value of x for which y = 2, is: |
| A. | \(\frac{5}{2} + \frac{1}{{\sqrt {\rm{e}} }}\) |
| B. | \(\frac{3}{2} - \frac{1}{{\sqrt {\rm{e}} }}\) |
| C. | \(\frac{1}{2} + \frac{1}{{\sqrt {\rm{e}} }}\) |
| D. | \(\frac{3}{2} - \sqrt {\rm{e}}\) |
| Answer» C. \(\frac{1}{2} + \frac{1}{{\sqrt {\rm{e}} }}\) | |