MCQOPTIONS
Saved Bookmarks
| 1. |
Consider the common emitter amplifier shown below with the following circuit parameters: = 100, gm = 0.3861 A/V, r0 = rp = 259 , Rs = 1 k , RB = 93 k , RC = 250 , RL = 1 kW, C1 = and C2 = 4.7mF.The lower cut-off frequency due to C2 is |
| A. | 33.9 Hz |
| B. | 27.1 Hz |
| C. | 13.6 Hz |
| D. | 16.9 Hz |
| Answer» B. 27.1 Hz | |