At point (1, 0, 3) on the surface 2x2 + 3y2 + z2 – 11 = 0, the directional derivative in the direction \(\vec a = \hat i + 2\hat j + \hat k\) is

At point (1, 0, 3) on the surface 2x2 + 3y2 + z2 – 11 = 0, the direc

1.	At point (1, 0, 3) on the surface 2x2 + 3y2 + z2 – 11 = 0, the directional derivative in the direction \(\vec a = \hat i + 2\hat j + \hat k\) is
A.	10
B.	\(\frac{{5}}{{3 }}\)
C.	\(\frac{{-5}}{{3 }}\)
D.	\(\frac{{10}}{{\sqrt 6 }}\)
Answer» E.

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At point (1, 0, 3) on the surface 2x2 + 3y2 + z2 – 11 = 0, the directional derivative in the direction \(\vec a = \hat i + 2\hat j + \hat k\) is

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