Area of a rectangular field is \[(2{{x}^{3}}-11{{x}^{2}}-4x+5)\,sq.\]units and side of a square field is (\[(2{{x}^{2}}+4)\]units. Find the difference between their areas (in sq. units).

\[4{{x}^{4}}+27{{x}^{2}}+4x-11\]

\[4{{x}^{4}}-2{{x}^{3}}-4x+11\]

\[4{{x}^{4}}-2{{x}^{3}}+27{{x}^{2}}+4x+11\]

\[4{{x}^{4}}+2{{x}^{3}}+27{{x}^{2}}+4x+11\]

Area of a rectangular field is \[(2{{x}^{3}}-11{{x}^{2}}-4x+5)\,sq.\]u

1.	Area of a rectangular field is \[(2{{x}^{3}}-11{{x}^{2}}-4x+5)\,sq.\]units and side of a square field is (\[(2{{x}^{2}}+4)\]units. Find the difference between their areas (in sq. units).
A.	\[4{{x}^{4}}-2{{x}^{3}}-4x+11\]
B.	\[4{{x}^{4}}-2{{x}^{3}}+27{{x}^{2}}+4x+11\]
C.	\[4{{x}^{4}}+27{{x}^{2}}+4x-11\]
D.	\[4{{x}^{4}}+2{{x}^{3}}+27{{x}^{2}}+4x+11\]
Answer» C. \[4{{x}^{4}}+27{{x}^{2}}+4x-11\]

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Area of a rectangular field is \[(2{{x}^{3}}-11{{x}^{2}}-4x+5)\,sq.\]units and side of a square field is (\[(2{{x}^{2}}+4)\]units. Find the difference between their areas (in sq. units).

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