An interior angle of a regular polygon is 5 times its exterior angle. – McqOptions

MCQOPTIONS

1.	An interior angle of a regular polygon is 5 times its exterior angle. Then the number of sides of the polygon is
A.	14
B.	16
C.	12
D.	18
Answer» D. 18

Discussion

No Comment Found

Related MCQs

In the adjoining figure, AB || CD, t is the traversal, EG and FG are the bisectors of BEE and DFE respectively, then EGF is equal to :
In the given figure, DE || BC and DE : BC = 3 : 5 the ratio of the areas of ADE and the trapezium BCED.
If H is the orthocentre of ABC, then the orthocentre of HBC is (fig. given) :
In a triangle ABC, the length of the sides AB, AC and BC are 3, 5 and 6 cm respectively. If a point D on BC is drawn such that the line AD bisects the angle A internally, then what is the length of BD?
X, Y are the mid-points of opposite sides AB and DC of a parallelogram ABCD. AY and DX are joined intersecting in P; CX and BY are joined intersecting in Q. Then PXQY is a :
ABCD is a rhombus with ABC = 56 , then ACD is equal to :
In the given figure, In a ABC , B = C. If AM is the bisector of BAC and AN BC, then MAN is equal to :
ABCD is a square, F is mid point of AB and E is a point on BC such that BE is one-third of BC. If area of FBE = 108 m2, then the length of AC is:
The diagonals of a rectangle ABCD meet at 0. If BOC = 44 , then OAD is equal to :
ABCD is a parallelogram P, Q, R and S are points on sides AB, BC, CD and DA respectively such that AP = DR. If the area of the parallelogram ABCD is 16 cm2, then the area of the quadrilateral PQRS is: