1.

AC is the diameter of the circumcircle of the cyclic quadrilateral ABCD. If. \[\angle \mathbf{BDC}=\mathbf{4}{{\mathbf{8}}^{{}^\circ }}\]then \[\angle \mathbf{ACB}\] is equal to

A.  \[{{42}^{{}^\circ }}\]      
B.  \[{{45}^{{}^\circ }}\]  
C.  \[{{48}^{{}^\circ }}\]        
D.  \[{{58}^{{}^\circ }}\]
Answer» B.  \[{{45}^{{}^\circ }}\]  


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