MCQOPTIONS
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| 1. |
AC is the diameter of the circumcircle of the cyclic quadrilateral ABCD. If. \[\angle \mathbf{BDC}=\mathbf{4}{{\mathbf{8}}^{{}^\circ }}\]then \[\angle \mathbf{ACB}\] is equal to |
| A. | \[{{42}^{{}^\circ }}\] |
| B. | \[{{45}^{{}^\circ }}\] |
| C. | \[{{48}^{{}^\circ }}\] |
| D. | \[{{58}^{{}^\circ }}\] |
| Answer» B. \[{{45}^{{}^\circ }}\] | |