ABCD is parallelogram, G is the point on AB such that AG = 2GB, E is point on DC such that CE = 2DE and F is the point on BC such that BF = 2FC. Then, match the following: Column-I Column-IIp\[ar(ADEG)\](i)\[\frac{1}{6}ar(ABCD)\]Q\[ar(\Delta EGB)\](ii)\[ar(GBCE)\]R\[ar(\Delta EFC)\](iii)\[ar(\Delta GBCE)\]S\[ar(\Delta EFC)\](iv)\[\frac{1}{2}ar(\Delta EBF)\]

ABCD is parallelogram, G is the point on AB such that AG = 2GB, E is p

1.	ABCD is parallelogram, G is the point on AB such that AG = 2GB, E is point on DC such that CE = 2DE and F is the point on BC such that BF = 2FC. Then, match the following: Column-I Column-IIp\[ar(ADEG)\](i)\[\frac{1}{6}ar(ABCD)\]Q\[ar(\Delta EGB)\](ii)\[ar(GBCE)\]R\[ar(\Delta EFC)\](iii)\[ar(\Delta GBCE)\]S\[ar(\Delta EFC)\](iv)\[\frac{1}{2}ar(\Delta EBF)\]
A.	P-iQ-iiR-iiiS-iv
B.	P-iiiQ-iR-ivS-ii
C.	P-iiiQ-iiR-ivS-i
D.	P-iiQ-iR-iiiS-iv
Answer» C. P-iiiQ-iiR-ivS-i

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