MCQOPTIONS
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| 1. |
ABCD is a parallelogram. BC is produced to Q such that BC = CQ. Then |
| A. | area \[\left( \Delta BCP \right)\] = area \[\left( \Delta DPQ \right)\] |
| B. | area \[\left( \Delta BCP \right)\] > area \[\left( \Delta DPQ \right)\] |
| C. | area \[\left( \Delta BCP \right)\] < area \[\left( \Delta DPQ \right)\] |
| D. | area \[\left( \Delta BCP \right)\] + area \[\left( \Delta DPQ \right)\] = area \[(\Delta \,BCD)\] |
| Answer» B. area \[\left( \Delta BCP \right)\] > area \[\left( \Delta DPQ \right)\] | |