1.

ABCD is a parallelogram. BC is produced to Q such that BC = CQ. Then

A. area \[\left( \Delta BCP \right)\] = area \[\left( \Delta DPQ \right)\]
B. area \[\left( \Delta BCP \right)\] > area \[\left( \Delta DPQ \right)\]
C. area \[\left( \Delta BCP \right)\] < area \[\left( \Delta DPQ \right)\]
D. area \[\left( \Delta BCP \right)\] + area \[\left( \Delta DPQ \right)\] = area \[(\Delta \,BCD)\]
Answer» B. area \[\left( \Delta BCP \right)\] > area \[\left( \Delta DPQ \right)\]


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