ABCD is a cyclic quadrilateral and 0 is the centre of the circle If \[\angle COD={{120}^{{}^\circ }}\]and \[\angle \mathbf{BAC}=\mathbf{6}{{\mathbf{0}}^{{}^\circ }}\], then the value of \[\angle \mathbf{BCD}\] is equal to

• A.  \[{{70}^{{}^\circ }}\]                       
• B.  \[{{90}^{{}^\circ }}\]            
• C.  \[{{60}^{{}^\circ }}\]   
• D.  \[{{80}^{{}^\circ }}\]