A value of α such that \(\mathop \smallint \nolimits_\alpha ^{\alpha + 1} \frac{{{\rm{d}}x}}{{\left( {x + \alpha } \right)\left( {x + \alpha + 1} \right)}} = {\rm{lo}}{{\rm{g}}_{\rm{e}}}\left( {\frac{9}{8}} \right)\) is:

A value of α such that \(\mathop \smallint \nolimits_\alpha ^{\alpha

1.	A value of α such that \(\mathop \smallint \nolimits_\alpha ^{\alpha + 1} \frac{{{\rm{d}}x}}{{\left( {x + \alpha } \right)\left( {x + \alpha + 1} \right)}} = {\rm{lo}}{{\rm{g}}_{\rm{e}}}\left( {\frac{9}{8}} \right)\) is:
A.	-2
B.	\(\frac{1}{2}\)
C.	\(- \frac{1}{2}\)
D.	2
Answer» B. \(\frac{1}{2}\)

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A value of α such that \(\mathop \smallint \nolimits_\alpha ^{\alpha + 1} \frac{{{\rm{d}}x}}{{\left( {x + \alpha } \right)\left( {x + \alpha + 1} \right)}} = {\rm{lo}}{{\rm{g}}_{\rm{e}}}\left( {\frac{9}{8}} \right)\) is:

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