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| 1. |
A square loop is carrying a steady current I and the magnitude of its magnetic dipole moment is m. If this square loop is changed to a circular loop and it carries the same current, the magnitude of the magnetic dipole moment of circular loop will be: |
| A. | \(\frac{{\rm{m}}}{{\rm{\pi }}}\) |
| B. | \(\frac{{3{\rm{m}}}}{{\rm{\pi }}}\) |
| C. | \({\rm{\;}}\frac{{2{\rm{m}}}}{{\rm{\pi }}}\) |
| D. | \({\rm{\;}}\frac{{4{\rm{m}}}}{{\rm{\pi }}}\) |
| Answer» E. | |