A solution contains $$F{{e}^{2+}},F{{e}^{3+}}$$ and $${{I}^{-}}$$ ions. This solution was treated with iodine at$$35{}^\circ C$$. $$E{}^\circ $$ for $$F{{e}^{3+}}/F{{e}^{2+}}$$ is + 0.77 V and $$E{}^\circ $$ for $${{I}_{2}}/2{{I}^{-}}=0.536V.$$ he favourable redox reaction is:

Question

A solution contains $$F{{e}^{2+}},F{{e}^{3+}}$$ and $${{I}^{-}}$$ ions. This solution was treated with iodine at$$35{}^\circ C$$. $$E{}^\circ $$ for $$F{{e}^{3+}}/F{{e}^{2+}}$$ is + 0.77 V and $$E{}^\circ $$ for $${{I}_{2}}/2{{I}^{-}}=0.536V.$$ he favourable redox reaction is:

TuteeHUB · Accepted Answer

$$F{{e}^{2+}}$$ will be oxidised to $$F{{e}^{3+}}$$

TuteeHUB · Answer

$${{I}_{2}}$$ will be reduced to $${{I}^{-}}$$

TuteeHUB · Answer

There will be no redox reaction

TuteeHUB · Answer

$${{I}^{-}}$$ will be oxidised to $${{I}_{2}}$$

1.	A solution contains \[F{{e}^{2+}},F{{e}^{3+}}\] and \[{{I}^{-}}\] ions. This solution was treated with iodine at\[35{}^\circ C\]. \[E{}^\circ \] for \[F{{e}^{3+}}/F{{e}^{2+}}\] is + 0.77 V and \[E{}^\circ \] for \[{{I}_{2}}/2{{I}^{-}}=0.536V.\] he favourable redox reaction is:
A.	\[{{I}_{2}}\] will be reduced to \[{{I}^{-}}\]
B.	There will be no redox reaction
C.	\[{{I}^{-}}\] will be oxidised to \[{{I}_{2}}\]
D.	\[F{{e}^{2+}}\] will be oxidised to \[F{{e}^{3+}}\]
Answer» D. \[F{{e}^{2+}}\] will be oxidised to \[F{{e}^{3+}}\]

A solution contains \[F{{e}^{2+}},F{{e}^{3+}}\] and \[{{I}^{-}}\] ions. This solution was treated with iodine at\[35{}^\circ C\]. \[E{}^\circ \] for \[F{{e}^{3+}}/F{{e}^{2+}}\] is + 0.77 V and \[E{}^\circ \] for \[{{I}_{2}}/2{{I}^{-}}=0.536V.\] he favourable redox reaction is:

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