A series RL circuit is excited by a voltage v(t) = Ve-at such that a = R/L. Then the circuit current is

A series RL circuit is excited by a voltage v(t) = Ve-at such that a =

1.	A series RL circuit is excited by a voltage v(t) = Ve-at such that a = R/L. Then the circuit current is
A.	<img src="/_files/images/electronics-and-communication-engineering/networks-analysis-and-synthesis/93-162-1.png">
B.	<img src="/_files/images/electronics-and-communication-engineering/networks-analysis-and-synthesis/93-162-2.png">
C.	<img src="/_files/images/electronics-and-communication-engineering/networks-analysis-and-synthesis/93-162-3.png">
D.	<img src="/_files/images/electronics-and-communication-engineering/networks-analysis-and-synthesis/93-162-4.png">
Answer» C. <img src="/_files/images/electronics-and-communication-engineering/networks-analysis-and-synthesis/93-162-3.png">