A satellite is revolving in a circular orbit at a distance of 2620 km from the surface of the earth. The time period of revolution of the satellite is (Radius of the earth = 6380 km, mass of the earth \[=6\times {{10}^{24}}kg,G=6.67\times {{10}^{-11}}N-{{m}^{2}}^{/}k{{g}^{2}})\]

A satellite is revolving in a circular orbit at a distance of 2620 km

1.	A satellite is revolving in a circular orbit at a distance of 2620 km from the surface of the earth. The time period of revolution of the satellite is (Radius of the earth = 6380 km, mass of the earth \[=6\times {{10}^{24}}kg,G=6.67\times {{10}^{-11}}N-{{m}^{2}}^{/}k{{g}^{2}})\]
A.	2.35 hours
B.	23.5 hours
C.	3.25 hours
D.	32.5 hours
Answer» B. 23.5 hours

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A satellite is revolving in a circular orbit at a distance of 2620 km from the surface of the earth. The time period of revolution of the satellite is (Radius of the earth = 6380 km, mass of the earth \[=6\times {{10}^{24}}kg,G=6.67\times {{10}^{-11}}N-{{m}^{2}}^{/}k{{g}^{2}})\]

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