A flat foot step bearing 20 cm in diameter supports a load of 2500 kg – McqOptions

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1.	A flat foot step bearing 20 cm in diameter supports a load of 2500 kgf. The shaft is running at 420 rpm and the co-efficient is 0.09. The power lost in overcoming friction at the bearing, will be equal to ___.
A.	650 watt
B.	880 watt
C.	659.7 watt
D.	680.20 watt
Answer» D. 680.20 watt

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