A circle is inscribed in ΔABC, touching AB, BC and AC at the points P, Q and R respectively. If AB - BC = 4 cm, AB - AC = 2 cm and the perimeter of ΔABC = 32 cm, then PB + AR is equal to∶

A circle is inscribed in ΔABC, touching AB, BC and AC at the points P

1.	A circle is inscribed in ΔABC, touching AB, BC and AC at the points P, Q and R respectively. If AB - BC = 4 cm, AB - AC = 2 cm and the perimeter of ΔABC = 32 cm, then PB + AR is equal to∶
A.	12 cm
B.	13 cm
C.	33/5 cm
D.	38/3 cm
Answer» E.

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A circle is inscribed in ΔABC, touching AB, BC and AC at the points P, Q and R respectively. If AB - BC = 4 cm, AB - AC = 2 cm and the perimeter of ΔABC = 32 cm, then PB + AR is equal to∶

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